PX284 - G1 - energy deviation

⟨E⟩=1Z∑iEiexp⁡(−βEi)=−1ZdZdβ ⟨E2⟩=1Z∑iEi2exp⁡(−βEi)=−1Zd2Zdβ2 d⟨E⟩dβ=−1Zd2Zdβ2+1Z2(dZdβ)2=−(⟨E2⟩−⟨E⟩2)=−σE2

which is the variance of energy

d⟨E⟩dβ=dTdβd⟨E⟩dT=−kBT2CV σE=TkBCV

conclusions