PX153 - I1 - introduction

definition

F′(x)=limδx→0F(x+δx)−F(x)δx=limδx→0∫Ax+δxf(x′).dx′−∫Axf(x′).dx′δx=limδx→0∫Ax+δxf(x′).dx′+∫xAf(x′).dx′δx=limδx→0∫xx+δxf(x′).dx′δx=limδx→0f(x′)δxδx=f(x)

a bit of maths analysis

limδx→0f(x+δx)−f(x)δx=?f′(x) limN→∞∑n=0Nf(xA+nxB−xAN)xB−xAN=?∫xAxBf(x′).dx′

a) riemann integral
Pasted image 20240110183649.png

A≈∑i=0N−1f(xi)(xi+1−xi) limN→∞∑i=0N−1f(xi)Δxi=∫0af(x′).dx′ ∫abudvdx.dx=∫abd(uv)dx.dx−∫abvdudx.dx=[uv]ab−∫abdudxv.dx

- substitutions:
$$ I = \int \frac{1}{(1-x)^{\frac{1}{2}}}.dx$$
- let x=sin⁡u , and dx=cos⁡u.du :
$$I = \int \frac{\cos u.du}{\cos u} = \int du = u = \sin^{-1} x$$
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