F3 - hankel transforms

Fν(k)=0f(r)Jν(kr)rdr

where, ν1/2

f(r)=0Fν(k)Jν(kr)kdk H0{2ur2+1rur+2uz2}=k2U+2z2U

where, U=H0u

0Jν(kr)Jν(kr)rdr=δ(kk)k,k,k>0

hankel functions

Hα(1)(x)=Jα(x)+iYα(x)Hα(2)(x)=Jα(x)iYα(x)