PX155 - B2 - continuous bodies

M=dm=0Lρ.dx=oLαx.dx=α[x22]0L=αL22

- similarly,$$\int x.dm=\int_0^L x\rho.dx =\int_o^L\alpha x^2 .dx = \alpha[\frac{x^3}{3}]_0^L= \frac{\alpha L^3}{3}$$
- hence,

xcm=x.dmdm=23L σ=MAM=πR22σ(=dm)

- slicing the semicircle vertically:
\1\n\2\n